10(a-5)=6(a-3)

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Solution for 10(a-5)=6(a-3) equation: 



10(a-5)=6(a-3)

We move all terms to the left:

10(a-5)-(6(a-3))=0

We multiply parentheses

10a-(6(a-3))-50=0



We calculate terms in parentheses: -(6(a-3)), so:

6(a-3)

We multiply parentheses

6a-18

Back to the equation:

-(6a-18)



We get rid of parentheses

10a-6a+18-50=0

We add all the numbers together, and all the variables

4a-32=0

We move all terms containing a to the left, all other terms to the right

4a=32

a=32/4

a=8

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