2-3(x-6)=3x-4(2x-3)

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Solution for 2-3(x-6)=3x-4(2x-3) equation: 



2-3(x-6)=3x-4(2x-3)

We move all terms to the left:

2-3(x-6)-(3x-4(2x-3))=0

We multiply parentheses

-3x-(3x-4(2x-3))+18+2=0



We calculate terms in parentheses: -(3x-4(2x-3)), so:

3x-4(2x-3)

We multiply parentheses

3x-8x+12

We add all the numbers together, and all the variables

-5x+12

Back to the equation:

-(-5x+12)



We add all the numbers together, and all the variables

-3x-(-5x+12)+20=0

We get rid of parentheses

-3x+5x-12+20=0

We add all the numbers together, and all the variables

2x+8=0

We move all terms containing x to the left, all other terms to the right

2x=-8

x=-8/2

x=-4

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