(3y+30)=(7y-10)

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Solution for (3y+30)=(7y-10) equation: 



(3y+30)=(7y-10)

We move all terms to the left:

(3y+30)-((7y-10))=0

We get rid of parentheses

3y-((7y-10))+30=0



We calculate terms in parentheses: -((7y-10)), so:

(7y-10)

We get rid of parentheses

7y-10

Back to the equation:

-(7y-10)



We get rid of parentheses

3y-7y+10+30=0

We add all the numbers together, and all the variables

-4y+40=0

We move all terms containing y to the left, all other terms to the right

-4y=-40

y=-40/-4

y=+10

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