3x-2=3(2x-1)-2(2x+1)

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Solution for 3x-2=3(2x-1)-2(2x+1) equation: 



3x-2=3(2x-1)-2(2x+1)

We move all terms to the left:

3x-2-(3(2x-1)-2(2x+1))=0



We calculate terms in parentheses: -(3(2x-1)-2(2x+1)), so:

3(2x-1)-2(2x+1)

We multiply parentheses

6x-4x-3-2

We add all the numbers together, and all the variables

2x-5

Back to the equation:

-(2x-5)



We get rid of parentheses

3x-2x+5-2=0

We add all the numbers together, and all the variables

x+3=0

We move all terms containing x to the left, all other terms to the right

x=-3

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