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2-(3x+1)3=2(7-6x)
We move all terms to the left:
2-(3x+1)3-(2(7-6x))=0
We add all the numbers together, and all the variables
-(3x+1)3-(2(-6x+7))+2=0
We multiply parentheses
-9x-(2(-6x+7))-3+2=0
We calculate terms in parentheses: -(2(-6x+7)), so:We add all the numbers together, and all the variables
2(-6x+7)
We multiply parentheses
-12x+14
Back to the equation:
-(-12x+14)
-9x-(-12x+14)-1=0
We get rid of parentheses
-9x+12x-14-1=0
We add all the numbers together, and all the variables
3x-15=0
We move all terms containing x to the left, all other terms to the right
3x=15
x=15/3
x=5
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