2+6(z-4)=3z-18+3z

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Solution for 2+6(z-4)=3z-18+3z equation: 



2+6(z-4)=3z-18+3z

We move all terms to the left:

2+6(z-4)-(3z-18+3z)=0

We add all the numbers together, and all the variables

6(z-4)-(6z-18)+2=0

We multiply parentheses

6z-(6z-18)-24+2=0

We get rid of parentheses

6z-6z+18-24+2=0

We add all the numbers together, and all the variables

-4!=0

There is no solution for this equation

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