2+4(k+2)=7(k+1)9

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Solution for 2+4(k+2)=7(k+1)9 equation: 



2+4(k+2)=7(k+1)9

We move all terms to the left:

2+4(k+2)-(7(k+1)9)=0

We multiply parentheses

4k-(7(k+1)9)+8+2=0



We calculate terms in parentheses: -(7(k+1)9), so:

7(k+1)9

We multiply parentheses

63k+63

Back to the equation:

-(63k+63)



We add all the numbers together, and all the variables

4k-(63k+63)+10=0

We get rid of parentheses

4k-63k-63+10=0

We add all the numbers together, and all the variables

-59k-53=0

We move all terms containing k to the left, all other terms to the right

-59k=53

k=53/-59

k=-53/59

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