-10-(3x+2)=6(4x-2x)+16

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Solution for -10-(3x+2)=6(4x-2x)+16 equation: 



-10-(3x+2)=6(4x-2x)+16

We move all terms to the left:

-10-(3x+2)-(6(4x-2x)+16)=0

We add all the numbers together, and all the variables

-(3x+2)-(6(+2x)+16)-10=0

We get rid of parentheses

-3x-(6(+2x)+16)-2-10=0



We calculate terms in parentheses: -(6(+2x)+16), so:

6(+2x)+16

We multiply parentheses

12x+16

Back to the equation:

-(12x+16)



We add all the numbers together, and all the variables

-3x-(12x+16)-12=0

We get rid of parentheses

-3x-12x-16-12=0

We add all the numbers together, and all the variables

-15x-28=0

We move all terms containing x to the left, all other terms to the right

-15x=28

x=28/-15

x=-1+13/15

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