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2(4x+2)-2(x-2)=-(2x+12)
We move all terms to the left:
2(4x+2)-2(x-2)-(-(2x+12))=0
We multiply parentheses
8x-2x-(-(2x+12))+4+4=0
We calculate terms in parentheses: -(-(2x+12)), so:We add all the numbers together, and all the variables
-(2x+12)
We get rid of parentheses
-2x-12
Back to the equation:
-(-2x-12)
6x-(-2x-12)+8=0
We get rid of parentheses
6x+2x+12+8=0
We add all the numbers together, and all the variables
8x+20=0
We move all terms containing x to the left, all other terms to the right
8x=-20
x=-20/8
x=-2+1/2
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