2+3(3x-4)=8-3(2x+1)

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Solution for 2+3(3x-4)=8-3(2x+1) equation: 



2+3(3x-4)=8-3(2x+1)

We move all terms to the left:

2+3(3x-4)-(8-3(2x+1))=0

We multiply parentheses

9x-(8-3(2x+1))-12+2=0



We calculate terms in parentheses: -(8-3(2x+1)), so:

8-3(2x+1)

determiningTheFunctionDomain
-3(2x+1)+8

We multiply parentheses

-6x-3+8

We add all the numbers together, and all the variables

-6x+5

Back to the equation:

-(-6x+5)



We add all the numbers together, and all the variables

9x-(-6x+5)-10=0

We get rid of parentheses

9x+6x-5-10=0

We add all the numbers together, and all the variables

15x-15=0

We move all terms containing x to the left, all other terms to the right

15x=15

x=15/15

x=1

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