-7y+3(y-2)=2

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Solution for -7y+3(y-2)=2 equation:



-7y+3(y-2)=2
We move all terms to the left:
-7y+3(y-2)-(2)=0
We multiply parentheses
-7y+3y-6-2=0
We add all the numbers together, and all the variables
-4y-8=0
We move all terms containing y to the left, all other terms to the right
-4y=8
y=8/-4
y=-2

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