7(2c+3)=3(4c+9)

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Solution for 7(2c+3)=3(4c+9) equation: 



7(2c+3)=3(4c+9)

We move all terms to the left:

7(2c+3)-(3(4c+9))=0

We multiply parentheses

14c-(3(4c+9))+21=0



We calculate terms in parentheses: -(3(4c+9)), so:

3(4c+9)

We multiply parentheses

12c+27

Back to the equation:

-(12c+27)



We get rid of parentheses

14c-12c-27+21=0

We add all the numbers together, and all the variables

2c-6=0

We move all terms containing c to the left, all other terms to the right

2c=6

c=6/2

c=3

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