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2(x+3)*x+3x=392
We move all terms to the left:
2(x+3)*x+3x-(392)=0
We add all the numbers together, and all the variables
3x+2(x+3)*x-392=0
We multiply parentheses
2x^2+3x+6x-392=0
We add all the numbers together, and all the variables
2x^2+9x-392=0
a = 2; b = 9; c = -392;
Δ = b2-4ac
Δ = 92-4·2·(-392)
Δ = 3217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{3217}}{2*2}=\frac{-9-\sqrt{3217}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{3217}}{2*2}=\frac{-9+\sqrt{3217}}{4} $
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