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9f^2+18f+8=0
a = 9; b = 18; c = +8;
Δ = b2-4ac
Δ = 182-4·9·8
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-6}{2*9}=\frac{-24}{18} =-1+1/3 $$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+6}{2*9}=\frac{-12}{18} =-2/3 $
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