3r-5(7-r)=5r-(2r-10)

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Solution for 3r-5(7-r)=5r-(2r-10) equation: 



3r-5(7-r)=5r-(2r-10)

We move all terms to the left:

3r-5(7-r)-(5r-(2r-10))=0

We add all the numbers together, and all the variables

3r-5(-1r+7)-(5r-(2r-10))=0

We multiply parentheses

3r+5r-(5r-(2r-10))-35=0



We calculate terms in parentheses: -(5r-(2r-10)), so:

5r-(2r-10)

We get rid of parentheses

5r-2r+10

We add all the numbers together, and all the variables

3r+10

Back to the equation:

-(3r+10)



We add all the numbers together, and all the variables

8r-(3r+10)-35=0

We get rid of parentheses

8r-3r-10-35=0

We add all the numbers together, and all the variables

5r-45=0

We move all terms containing r to the left, all other terms to the right

5r=45

r=45/5

r=9

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