2(z+5)+5(z+z)=10(z-1)

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Solution for 2(z+5)+5(z+z)=10(z-1) equation: 



2(z+5)+5(z+z)=10(z-1)

We move all terms to the left:

2(z+5)+5(z+z)-(10(z-1))=0

We add all the numbers together, and all the variables

2(z+5)+5(+2z)-(10(z-1))=0

We multiply parentheses

2z+10z-(10(z-1))+10=0



We calculate terms in parentheses: -(10(z-1)), so:

10(z-1)

We multiply parentheses

10z-10

Back to the equation:

-(10z-10)



We add all the numbers together, and all the variables

12z-(10z-10)+10=0

We get rid of parentheses

12z-10z+10+10=0

We add all the numbers together, and all the variables

2z+20=0

We move all terms containing z to the left, all other terms to the right

2z=-20

z=-20/2

z=-10

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