(4/5)x+(2/5)=-(6/5)

Solution for (4/5)x+(2/5)=-(6/5) equation:

(4/5)x+(2/5)=-(6/5)

We move all terms to the left:

(4/5)x+(2/5)-(-(6/5))=0


Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+4/5)x+(+2/5)-(-(+6/5))=0

We multiply parentheses

4x^2+(+2/5)-(-(+6/5))=0

We get rid of parentheses

4x^2+2/5-(-(+6/5))=0

We calculate fractions


4x^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{8}=0$