(2x+8)=(3x+19)+(7x+5)

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Solution for (2x+8)=(3x+19)+(7x+5) equation: 



(2x+8)=(3x+19)+(7x+5)

We move all terms to the left:

(2x+8)-((3x+19)+(7x+5))=0

We get rid of parentheses

2x-((3x+19)+(7x+5))+8=0



We calculate terms in parentheses: -((3x+19)+(7x+5)), so:

(3x+19)+(7x+5)

We get rid of parentheses

3x+7x+19+5

We add all the numbers together, and all the variables

10x+24

Back to the equation:

-(10x+24)



We get rid of parentheses

2x-10x-24+8=0

We add all the numbers together, and all the variables

-8x-16=0

We move all terms containing x to the left, all other terms to the right

-8x=16

x=16/-8

x=-2

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