(11x+3)=(2x+16)+(x+7)

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Solution for (11x+3)=(2x+16)+(x+7) equation: 



(11x+3)=(2x+16)+(x+7)

We move all terms to the left:

(11x+3)-((2x+16)+(x+7))=0

We get rid of parentheses

11x-((2x+16)+(x+7))+3=0



We calculate terms in parentheses: -((2x+16)+(x+7)), so:

(2x+16)+(x+7)

We get rid of parentheses

2x+x+16+7

We add all the numbers together, and all the variables

3x+23

Back to the equation:

-(3x+23)



We get rid of parentheses

11x-3x-23+3=0

We add all the numbers together, and all the variables

8x-20=0

We move all terms containing x to the left, all other terms to the right

8x=20

x=20/8

x=2+1/2

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