4(3p+2)-(6p-1)=2(p-8)-6(7p-4)

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Solution for 4(3p+2)-(6p-1)=2(p-8)-6(7p-4) equation: 



4(3p+2)-(6p-1)=2(p-8)-6(7p-4)

We move all terms to the left:

4(3p+2)-(6p-1)-(2(p-8)-6(7p-4))=0

We multiply parentheses

12p-(6p-1)-(2(p-8)-6(7p-4))+8=0

We get rid of parentheses

12p-6p-(2(p-8)-6(7p-4))+1+8=0



We calculate terms in parentheses: -(2(p-8)-6(7p-4)), so:

2(p-8)-6(7p-4)

We multiply parentheses

2p-42p-16+24

We add all the numbers together, and all the variables

-40p+8

Back to the equation:

-(-40p+8)



We add all the numbers together, and all the variables

6p-(-40p+8)+9=0

We get rid of parentheses

6p+40p-8+9=0

We add all the numbers together, and all the variables

46p+1=0

We move all terms containing p to the left, all other terms to the right

46p=-1

p=-1/46

p=-1/46

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