2(z+4)=6z

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Solution for 2(z+4)=6z equation: 



2(z+4)=6z

We move all terms to the left:

2(z+4)-(6z)=0

We add all the numbers together, and all the variables

-6z+2(z+4)=0

We multiply parentheses

-6z+2z+8=0

We add all the numbers together, and all the variables

-4z+8=0

We move all terms containing z to the left, all other terms to the right

-4z=-8

z=-8/-4

z=+2

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