(n+1)(n+2)=30(20000)

Solution for (n+1)(n+2)=30(20000) equation:

(n+1)(n+2)=30(20000)

We move all terms to the left:

(n+1)(n+2)-(30(20000))=0

determiningTheFunctionDomain
(n+1)(n+2)-3020000=0

We multiply parentheses ..

(+n^2+2n+n+2)-3020000=0

We get rid of parentheses

n^2+2n+n+2-3020000=0

We add all the numbers together, and all the variables

n^2+3n-3019998=0

a = 1; b = 3; c = -3019998;
Δ = b2-4ac
Δ = 32-4·1·(-3019998)
Δ = 12080001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{12080001}}{2*1}=\frac{-3-\sqrt{12080001}}{2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{12080001}}{2*1}=\frac{-3+\sqrt{12080001}}{2}
$