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3(x-14)=x-5(x+13)
We move all terms to the left:
3(x-14)-(x-5(x+13))=0
We multiply parentheses
3x-(x-5(x+13))-42=0
We calculate terms in parentheses: -(x-5(x+13)), so:We get rid of parentheses
x-5(x+13)
We multiply parentheses
x-5x-65
We add all the numbers together, and all the variables
-4x-65
Back to the equation:
-(-4x-65)
3x+4x+65-42=0
We add all the numbers together, and all the variables
7x+23=0
We move all terms containing x to the left, all other terms to the right
7x=-23
x=-23/7
x=-3+2/7
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