(2/x)+((4x+16)/(3x))=1/3

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Solution for (2/x)+((4x+16)/(3x))=1/3 equation: 



(2/x)+((4x+16)/(3x))=1/3

We move all terms to the left:

(2/x)+((4x+16)/(3x))-(1/3)=0



Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+2/x)+((4x+16)/3x)-(+1/3)=0

We get rid of parentheses

2/x+((4x+16)/3x)-1/3=0

We calculate fractions


18x/9x^2+(((4x+16)*x)/9x^2+(-x)/9x^2=0

We can not solve this equation

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