2(y-2)=4y+1-2(-2y-2)

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Solution for 2(y-2)=4y+1-2(-2y-2) equation: 



2(y-2)=4y+1-2(-2y-2)

We move all terms to the left:

2(y-2)-(4y+1-2(-2y-2))=0

We multiply parentheses

2y-(4y+1-2(-2y-2))-4=0



We calculate terms in parentheses: -(4y+1-2(-2y-2)), so:

4y+1-2(-2y-2)

determiningTheFunctionDomain
4y-2(-2y-2)+1

We multiply parentheses

4y+4y+4+1

We add all the numbers together, and all the variables

8y+5

Back to the equation:

-(8y+5)



We get rid of parentheses

2y-8y-5-4=0

We add all the numbers together, and all the variables

-6y-9=0

We move all terms containing y to the left, all other terms to the right

-6y=9

y=9/-6

y=-1+1/2

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