-3(2x-4)+8x=23

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Solution for -3(2x-4)+8x=23 equation: 



-3(2x-4)+8x=23

We move all terms to the left:

-3(2x-4)+8x-(23)=0

We add all the numbers together, and all the variables

8x-3(2x-4)-23=0

We multiply parentheses

8x-6x+12-23=0

We add all the numbers together, and all the variables

2x-11=0

We move all terms containing x to the left, all other terms to the right

2x=11

x=11/2

x=5+1/2

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