360=1/3x+(x-10)+(x-20)+40

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Solution for 360=1/3x+(x-10)+(x-20)+40 equation: 



360=1/3x+(x-10)+(x-20)+40

We move all terms to the left:

360-(1/3x+(x-10)+(x-20)+40)=0



Domain of the equation: 3x+(x-10)+(x-20)+40)!=0

x∈R



We multiply all the terms by the denominator


-(1+360*3x+(x-10)+(x-20)+40)=0



We calculate terms in parentheses: -(1+360*3x+(x-10)+(x-20)+40), so:

1+360*3x+(x-10)+(x-20)+40

determiningTheFunctionDomain
360*3x+(x-10)+(x-20)+1+40

We add all the numbers together, and all the variables

360*3x+(x-10)+(x-20)+41

Wy multiply elements

1080x+(x-10)+(x-20)+41

We get rid of parentheses

1080x+x+x-10-20+41

We add all the numbers together, and all the variables

1082x+11

Back to the equation:

-(1082x+11)



We get rid of parentheses

-1082x-11=0

We move all terms containing x to the left, all other terms to the right

-1082x=11

x=11/-1082

x=-11/1082

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