2(y-1)=5y+4-3(-5y-1)

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Solution for 2(y-1)=5y+4-3(-5y-1) equation: 



2(y-1)=5y+4-3(-5y-1)

We move all terms to the left:

2(y-1)-(5y+4-3(-5y-1))=0

We multiply parentheses

2y-(5y+4-3(-5y-1))-2=0



We calculate terms in parentheses: -(5y+4-3(-5y-1)), so:

5y+4-3(-5y-1)

determiningTheFunctionDomain
5y-3(-5y-1)+4

We multiply parentheses

5y+15y+3+4

We add all the numbers together, and all the variables

20y+7

Back to the equation:

-(20y+7)



We get rid of parentheses

2y-20y-7-2=0

We add all the numbers together, and all the variables

-18y-9=0

We move all terms containing y to the left, all other terms to the right

-18y=9

y=9/-18

y=-1/2

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