4(-z+5)=32

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Solution for 4(-z+5)=32 equation: 



4(-z+5)=32

We move all terms to the left:

4(-z+5)-(32)=0

We add all the numbers together, and all the variables

4(-1z+5)-32=0

We multiply parentheses

-4z+20-32=0

We add all the numbers together, and all the variables

-4z-12=0

We move all terms containing z to the left, all other terms to the right

-4z=12

z=12/-4

z=-3

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