If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(2x+1)(x-7)/11(x-7)=2x+1/11
We move all terms to the left:
(2x+1)(x-7)/11(x-7)-(2x+1/11)=0
Domain of the equation: 11(x-7)!=0We add all the numbers together, and all the variables
x∈R
(2x+1)(x-7)/11(x-7)-(+2x+1/11)=0
We get rid of parentheses
(2x+1)(x-7)/11(x-7)-2x-1/11=0
We multiply parentheses ..
(+2x^2-14x+x-7)/11(x-7)-2x-1/11=0
We calculate fractions
-2x=0
x=0/-2
x=0
| 3(5r+8)=4(6r+9) | | 12x+12=14x+12 | | H(t)=-4.9t^2+22t+5.5 | | 13=u/ | | 26r+27=-39r-10 | | 2q2–3q+4=0 | | -10=v/3+5 | | 5r-4=1/5(5+20r) | | q2+q+1=0 | | p2+3p+7=0 | | A-1=-16-2a | | 4z2+9z+4=0 | | 5-5k=45 | | 3u2+6u+3=0 | | 0.5(x-4)=-x-5 | | 7x+6=7x+9 | | 9(w+4)=7w+32 | | 29=18+2x | | 0.5x-9=11 | | 9d-4=41 | | 9r+29=83 | | -7-2m=-3m-1 | | 5x−3=12 | | 5+6v=59 | | 5g-9+6=12 | | k=-2+3/5 | | -3m+17=-61 | | -6(1-6r)=2(r+30 | | 3(x-2)=6+3x | | (2x-1)^2=36 | | 5(x-6)-2x=3(x+10) | | 9k+4=4k-9 |