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5r-4=1/5(5+20r)
We move all terms to the left:
5r-4-(1/5(5+20r))=0
Domain of the equation: 5(5+20r))!=0We add all the numbers together, and all the variables
r∈R
5r-(1/5(20r+5))-4=0
We multiply all the terms by the denominator
5r*5(20r+5))-(1-4*5(20r+5))=0
Wy multiply elements
25r^2(2-20r(2=0
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