2(y-1)-3(1-2y)=2(y-1)-3y+4

Solution for 2(y-1)-3(1-2y)=2(y-1)-3y+4 equation:

2(y-1)-3(1-2y)=2(y-1)-3y+4

We move all terms to the left:

2(y-1)-3(1-2y)-(2(y-1)-3y+4)=0

We add all the numbers together, and all the variables

2(y-1)-3(-2y+1)-(2(y-1)-3y+4)=0

We multiply parentheses

2y+6y-(2(y-1)-3y+4)-2-3=0


We calculate terms in parentheses: -(2(y-1)-3y+4), so:

2(y-1)-3y+4

We add all the numbers together, and all the variables

-3y+2(y-1)+4

We multiply parentheses

-3y+2y-2+4

We add all the numbers together, and all the variables

-1y+2

Back to the equation:

-(-1y+2)


We add all the numbers together, and all the variables

8y-(-1y+2)-5=0

We get rid of parentheses

8y+1y-2-5=0

We add all the numbers together, and all the variables

9y-7=0

We move all terms containing y to the left, all other terms to the right

9y=7

y=7/9

y=7/9