-5y-3(2+y)=3y-4(1+y)+5

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Solution for -5y-3(2+y)=3y-4(1+y)+5 equation:



-5y-3(2+y)=3y-4(1+y)+5
We move all terms to the left:
-5y-3(2+y)-(3y-4(1+y)+5)=0
We add all the numbers together, and all the variables
-5y-3(y+2)-(3y-4(y+1)+5)=0
We multiply parentheses
-5y-3y-(3y-4(y+1)+5)-6=0
We calculate terms in parentheses: -(3y-4(y+1)+5), so:
3y-4(y+1)+5
We multiply parentheses
3y-4y-4+5
We add all the numbers together, and all the variables
-1y+1
Back to the equation:
-(-1y+1)
We add all the numbers together, and all the variables
-8y-(-1y+1)-6=0
We get rid of parentheses
-8y+1y-1-6=0
We add all the numbers together, and all the variables
-7y-7=0
We move all terms containing y to the left, all other terms to the right
-7y=7
y=7/-7
y=-1

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