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5-3x=1/2x-7
We move all terms to the left:
5-3x-(1/2x-7)=0
Domain of the equation: 2x-7)!=0We get rid of parentheses
x∈R
-3x-1/2x+7+5=0
We multiply all the terms by the denominator
-3x*2x+7*2x+5*2x-1=0
Wy multiply elements
-6x^2+14x+10x-1=0
We add all the numbers together, and all the variables
-6x^2+24x-1=0
a = -6; b = 24; c = -1;
Δ = b2-4ac
Δ = 242-4·(-6)·(-1)
Δ = 552
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{552}=\sqrt{4*138}=\sqrt{4}*\sqrt{138}=2\sqrt{138}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-2\sqrt{138}}{2*-6}=\frac{-24-2\sqrt{138}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+2\sqrt{138}}{2*-6}=\frac{-24+2\sqrt{138}}{-12} $
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