2(y+5)=-8(4-y)

Solution for 2(y+5)=-8(4-y) equation:

2(y+5)=-8(4-y)

We move all terms to the left:

2(y+5)-(-8(4-y))=0

We add all the numbers together, and all the variables

2(y+5)-(-8(-1y+4))=0

We multiply parentheses

2y-(-8(-1y+4))+10=0


We calculate terms in parentheses: -(-8(-1y+4)), so:

-8(-1y+4)

We multiply parentheses

8y-32

Back to the equation:

-(8y-32)


We get rid of parentheses

2y-8y+32+10=0

We add all the numbers together, and all the variables

-6y+42=0

We move all terms containing y to the left, all other terms to the right

-6y=-42

y=-42/-6

y=+7