10(x-2)+5=2(x-8)+33

Solution for 10(x-2)+5=2(x-8)+33 equation:

10(x-2)+5=2(x-8)+33

We move all terms to the left:

10(x-2)+5-(2(x-8)+33)=0

We multiply parentheses

10x-(2(x-8)+33)-20+5=0


We calculate terms in parentheses: -(2(x-8)+33), so:

2(x-8)+33

We multiply parentheses

2x-16+33

We add all the numbers together, and all the variables

2x+17

Back to the equation:

-(2x+17)


We add all the numbers together, and all the variables

10x-(2x+17)-15=0

We get rid of parentheses

10x-2x-17-15=0

We add all the numbers together, and all the variables

8x-32=0

We move all terms containing x to the left, all other terms to the right

8x=32

x=32/8

x=4