10(d+2)=6(d+8)

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Solution for 10(d+2)=6(d+8) equation: 



10(d+2)=6(d+8)

We move all terms to the left:

10(d+2)-(6(d+8))=0

We multiply parentheses

10d-(6(d+8))+20=0



We calculate terms in parentheses: -(6(d+8)), so:

6(d+8)

We multiply parentheses

6d+48

Back to the equation:

-(6d+48)



We get rid of parentheses

10d-6d-48+20=0

We add all the numbers together, and all the variables

4d-28=0

We move all terms containing d to the left, all other terms to the right

4d=28

d=28/4

d=7

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