-244=3(5-9b)+11

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Solution for -244=3(5-9b)+11 equation: 



-244=3(5-9b)+11

We move all terms to the left:

-244-(3(5-9b)+11)=0

We add all the numbers together, and all the variables

-(3(-9b+5)+11)-244=0



We calculate terms in parentheses: -(3(-9b+5)+11), so:

3(-9b+5)+11

We multiply parentheses

-27b+15+11

We add all the numbers together, and all the variables

-27b+26

Back to the equation:

-(-27b+26)



We get rid of parentheses

27b-26-244=0

We add all the numbers together, and all the variables

27b-270=0

We move all terms containing b to the left, all other terms to the right

27b=270

b=270/27

b=10

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