2(x-6)+x=3(x-4)

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Solution for 2(x-6)+x=3(x-4) equation: 



2(x-6)+x=3(x-4)

We move all terms to the left:

2(x-6)+x-(3(x-4))=0

We add all the numbers together, and all the variables

x+2(x-6)-(3(x-4))=0

We multiply parentheses

x+2x-(3(x-4))-12=0



We calculate terms in parentheses: -(3(x-4)), so:

3(x-4)

We multiply parentheses

3x-12

Back to the equation:

-(3x-12)



We add all the numbers together, and all the variables

3x-(3x-12)-12=0

We get rid of parentheses

3x-3x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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