2/7y+3/5y=1

Solution for 2/7y+3/5y=1 equation:

2/7y+3/5y=1

We move all terms to the left:

2/7y+3/5y-(1)=0


Domain of the equation: 7y!=0

y!=0/7

y!=0

y∈R



Domain of the equation: 5y!=0

y!=0/5

y!=0

y∈R


We calculate fractions


10y/35y^2+21y/35y^2-1=0

We multiply all the terms by the denominator


10y+21y-1*35y^2=0

We add all the numbers together, and all the variables

31y-1*35y^2=0

Wy multiply elements

-35y^2+31y=0

a = -35; b = 31; c = 0;
Δ = b2-4ac
Δ = 312-4·(-35)·0
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-31}{2*-35}=\frac{-62}{-70}
=31/35
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+31}{2*-35}=\frac{0}{-70}
=0
$