2(x-5)=4x2-(x+5)

Solution for 2(x-5)=4x2-(x+5) equation:

2(x-5)=4x^2-(x+5)

We move all terms to the left:

2(x-5)-(4x^2-(x+5))=0

We multiply parentheses

2x-(4x^2-(x+5))-10=0


We calculate terms in parentheses: -(4x^2-(x+5)), so:

4x^2-(x+5)

We get rid of parentheses

4x^2-x-5

We add all the numbers together, and all the variables

4x^2-1x-5

Back to the equation:

-(4x^2-1x-5)


We get rid of parentheses

-4x^2+2x+1x+5-10=0

We add all the numbers together, and all the variables

-4x^2+3x-5=0

a = -4; b = 3; c = -5;
Δ = b2-4ac
Δ = 32-4·(-4)·(-5)
Δ = -71
Delta is less than zero, so there is no solution for the equation