2(x-5)+3(x-2)=8+7(x+4)

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Solution for 2(x-5)+3(x-2)=8+7(x+4) equation: 



2(x-5)+3(x-2)=8+7(x+4)

We move all terms to the left:

2(x-5)+3(x-2)-(8+7(x+4))=0

We multiply parentheses

2x+3x-(8+7(x+4))-10-6=0



We calculate terms in parentheses: -(8+7(x+4)), so:

8+7(x+4)

determiningTheFunctionDomain
7(x+4)+8

We multiply parentheses

7x+28+8

We add all the numbers together, and all the variables

7x+36

Back to the equation:

-(7x+36)



We add all the numbers together, and all the variables

5x-(7x+36)-16=0

We get rid of parentheses

5x-7x-36-16=0

We add all the numbers together, and all the variables

-2x-52=0

We move all terms containing x to the left, all other terms to the right

-2x=52

x=52/-2

x=-26

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