2(x-4)/4=3(x-2)/5

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Solution for 2(x-4)/4=3(x-2)/5 equation: 



2(x-4)/4=3(x-2)/5

We move all terms to the left:

2(x-4)/4-(3(x-2)/5)=0

We calculate fractions


2x/()+(-(3(x-2)*4)/()=0



We calculate terms in parentheses: +(-(3(x-2)*4)/(), so:

-(3(x-2)*4)/(

We multiply all the terms by the denominator


-(3(x-2)*4)



We calculate terms in parentheses: -(3(x-2)*4), so:

3(x-2)*4

We multiply parentheses

12x-24

Back to the equation:

-(12x-24)



We get rid of parentheses

-12x+24

Back to the equation:

+(-12x+24)



We get rid of parentheses

2x/()-12x+24=0

We multiply all the terms by the denominator


2x-12x*()+24*()=0

We add all the numbers together, and all the variables

2x-12x*()=0

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