2(x-4)+3=3(x+4)-5

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Solution for 2(x-4)+3=3(x+4)-5 equation: 



2(x-4)+3=3(x+4)-5

We move all terms to the left:

2(x-4)+3-(3(x+4)-5)=0

We multiply parentheses

2x-(3(x+4)-5)-8+3=0



We calculate terms in parentheses: -(3(x+4)-5), so:

3(x+4)-5

We multiply parentheses

3x+12-5

We add all the numbers together, and all the variables

3x+7

Back to the equation:

-(3x+7)



We add all the numbers together, and all the variables

2x-(3x+7)-5=0

We get rid of parentheses

2x-3x-7-5=0

We add all the numbers together, and all the variables

-1x-12=0

We move all terms containing x to the left, all other terms to the right

-x=12

x=12/-1

x=-12

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