5(k-2)=10(3k+19)

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Solution for 5(k-2)=10(3k+19) equation: 



5(k-2)=10(3k+19)

We move all terms to the left:

5(k-2)-(10(3k+19))=0

We multiply parentheses

5k-(10(3k+19))-10=0



We calculate terms in parentheses: -(10(3k+19)), so:

10(3k+19)

We multiply parentheses

30k+190

Back to the equation:

-(30k+190)



We get rid of parentheses

5k-30k-190-10=0

We add all the numbers together, and all the variables

-25k-200=0

We move all terms containing k to the left, all other terms to the right

-25k=200

k=200/-25

k=-8

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