(24x+12)(x+1)=0

Solution for (24x+12)(x+1)=0 equation:

(24x+12)(x+1)=0

We multiply parentheses ..

(+24x^2+24x+12x+12)=0

We get rid of parentheses

24x^2+24x+12x+12=0

We add all the numbers together, and all the variables

24x^2+36x+12=0

a = 24; b = 36; c = +12;
Δ = b2-4ac
Δ = 362-4·24·12
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-12}{2*24}=\frac{-48}{48}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+12}{2*24}=\frac{-24}{48}
=-1/2
$