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2(x-4)(3x+5)=0
We multiply parentheses ..
2(+3x^2+5x-12x-20)=0
We multiply parentheses
6x^2+10x-24x-40=0
We add all the numbers together, and all the variables
6x^2-14x-40=0
a = 6; b = -14; c = -40;
Δ = b2-4ac
Δ = -142-4·6·(-40)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-34}{2*6}=\frac{-20}{12} =-1+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+34}{2*6}=\frac{48}{12} =4 $
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