4(t-4)+8t=6(2t+4)-10

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Solution for 4(t-4)+8t=6(2t+4)-10 equation: 



4(t-4)+8t=6(2t+4)-10

We move all terms to the left:

4(t-4)+8t-(6(2t+4)-10)=0

We add all the numbers together, and all the variables

8t+4(t-4)-(6(2t+4)-10)=0

We multiply parentheses

8t+4t-(6(2t+4)-10)-16=0



We calculate terms in parentheses: -(6(2t+4)-10), so:

6(2t+4)-10

We multiply parentheses

12t+24-10

We add all the numbers together, and all the variables

12t+14

Back to the equation:

-(12t+14)



We add all the numbers together, and all the variables

12t-(12t+14)-16=0

We get rid of parentheses

12t-12t-14-16=0

We add all the numbers together, and all the variables

-30!=0

There is no solution for this equation

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