8x-4(x-6)=2(x-3)+4

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Solution for 8x-4(x-6)=2(x-3)+4 equation: 



8x-4(x-6)=2(x-3)+4

We move all terms to the left:

8x-4(x-6)-(2(x-3)+4)=0

We multiply parentheses

8x-4x-(2(x-3)+4)+24=0



We calculate terms in parentheses: -(2(x-3)+4), so:

2(x-3)+4

We multiply parentheses

2x-6+4

We add all the numbers together, and all the variables

2x-2

Back to the equation:

-(2x-2)



We add all the numbers together, and all the variables

4x-(2x-2)+24=0

We get rid of parentheses

4x-2x+2+24=0

We add all the numbers together, and all the variables

2x+26=0

We move all terms containing x to the left, all other terms to the right

2x=-26

x=-26/2

x=-13

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