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2(x-3)+5=4(x+5)-3x
We move all terms to the left:
2(x-3)+5-(4(x+5)-3x)=0
We multiply parentheses
2x-(4(x+5)-3x)-6+5=0
We calculate terms in parentheses: -(4(x+5)-3x), so:We add all the numbers together, and all the variables
4(x+5)-3x
We add all the numbers together, and all the variables
-3x+4(x+5)
We multiply parentheses
-3x+4x+20
We add all the numbers together, and all the variables
x+20
Back to the equation:
-(x+20)
2x-(x+20)-1=0
We get rid of parentheses
2x-x-20-1=0
We add all the numbers together, and all the variables
x-21=0
We move all terms containing x to the left, all other terms to the right
x=21
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